#Catholic #catechesis #liturgy #biblestudy author • dad • VP Dev @CleanDNS • coder • astronomer (@nightskyjeff) • writer
Lawrenceville, NJ
Joined May 2009
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- free PDFs of two catechetical books I authored on the Mass
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Happy dedication & consecration of the Major Papal, Patriarchal & Roman Archbasilica, Metropolitan & Primatial Cathedral of the Most Holy Savior & Saints John the Baptist & the Evangelist in Lateran, Mother & Head of All Churches in Rome & in the World to those who celebrate.
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Some of y'all have a saint's memorial on your birthday.
I've got the Mother and Head of All Churches in Rome and in the World.
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Finally finished watching Quantumania last night. One of the most blah MCU movies I can think of.
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Jumping off the 3-meter diving board into the deep end of the pool freshman year of college during NROTC training, surfacing (coughing and flailing my limbs because I can't swim) and having the SSgt yell "PINYAN, CAN YOU SWIM?" -- "Sir, no sir." -- "GET THE HELL OUT OF MY POOL!"
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Took my seven year old to the @met_cloisters today and he loved it.
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Xavier, because I thought Francis of Assisi was Francis Xavier of Assisi, and I thought Xavier sounded better than Francis.
As it turns out, Francis Xavier was a decent choice after all.
Jeffrey "not using AI if I can help it" Pinyan retweeted
A British Jew is waiting in line to be knighted by the Queen. He is to kneel in front of her and recite a sentence in Latin when she taps him on the shoulders with her sword.
However, when his turn comes, he panics in the excitement of the moment and forgets the Latin. Then, thinking fast, he recites the only other sentence he knows in a foreign language, which he remembers from the Passover Seder:
"Ma nishtana ha layla ha zeh mi kol ha laylot."
Puzzled, Her Majesty turns to her advisor and whispers, "Why is this knight different from all other knights?"
I simplified the problem to just five cards { 2c, Ac, Ad, Ah, As } (I realized later I could have simplified it to just THREE cards), and calculated the probabilities, and found that P(2c | Ax) = P(As | Ax).
It's equally likely.
You shuffle a standard deck of playing cards uniformly at random, and then turn them over one at a time. After you flip over the first ace, is the next card more likely to be the ace of spades or the two of clubs?
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P(start w/ 2c Ax) = 1/5
P(start w/ 2c Ax As) = 1/4
P(As | start w/ 2c Ax) = 1/5 * 1/4 = 1/20
P(start w/ Acdh) = 3/5
P(start w/ Acdh As) = 1/4
P(As | start w/ Acdh) = 3/5 * 1/4 = 3/20
>> P(As) = 1/20 + 3/20 = 4/20 = 1/5
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Ooh. I see a number of possibilities here:
1. two of clubs comes before the first ace (which is not the aces of spades)
2. first ace (which is not the ace of spades) comes before the two of clubs
3. first ace (which IS the ace of spades) comes before the two of clubs
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1. 2C is Nth card, before first ace (not AS), prob of 2C = 0, prob of AS = 1/(52-N)
2. Ax (not AS) is Nth card, before 2C, prob of 2C = 1/(52-N), prob of AS = 1/(52-N)
3. Ax (is AS) is Nth card, before 2C, prob of 2C = 1/(52-N), prob of AS = 0
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